WebFeb 4, 2024 · 3 Answers. XPath 1.0 doesn't handle regex natively, you could try something like. (as pointed out by paul t, //* [boolean (number (substring-before (substring-after (@id, "sometext"), "_text")))] could be used to perform the same check your original regex does, if you need to check for middle digits as well) Yup, regex support would obviously ...

java - How to check if an element exists in the XML using XPath ...

WebSorted by: 1. Firstly, you need to declare a as list of string like: List a = new ArrayList<> (); Secondly, since text is a List you should get the text of the web element and then compare the getText () of the link of anchor tag. So instead of a = text.get (i).toString (); it should be a.add (text.get (i).getText ());. highest rated nattokinase

Java XPath Tutorial (with Examples) - HowToDoInJava

WebMay 11, 2024 · A Document ( org.w3c.dom.Document) represents the entire XML document, is the root of the document tree, provides our first access to data: XPath xPath = … WebFeb 11, 2014 · How XPath matches. Match only 1 (exact match), barak's answer. ... Class By.ByClassName is defined in By.java as follows: /** * Find elements based on the value of the "class" attribute. If an element has multiple classes, then * this will match against each of them. For example, if the value is "one two onone", then the * class names "one" and ... http://duoduokou.com/java/50847420985694090951.html how has new orleans improved since katrina